Commit c0232ae8 authored by Lin Feng's avatar Lin Feng Committed by Linus Torvalds
Browse files

mm: memblock: fix wrong memmove size in memblock_merge_regions()

The memmove span covers from (next+1) to the end of the array, and the
index of next is (i+1), so the index of (next+1) is (i+2).  So the size
of remaining array elements is (type->cnt - (i + 2)).

Since the remaining elements of the memblock array are move forward by
one element and there is only one additional element caused by this bug.
So there won't be any write overflow here but read overflow.  It may
read one more element out of the array address if the array happens to
be full.  Commonly it doesn't matter at all but if the array happens to
be located at the end a memblock, it may cause a invalid read operation
for the physical address doesn't exist.

There are 2 *happens to be* here, so I think the probability is quite
low, I don't know if any guy is haunted by this bug before.

Mostly I think it's user-invisible.

Signed-off-by: default avatarLin Feng <>
Acked-by: default avatarTejun Heo <>
Reviewed-by: default avatarWanpeng Li <>
Signed-off-by: default avatarAndrew Morton <>
Signed-off-by: default avatarLinus Torvalds <>
parent 552f0cc7
......@@ -314,7 +314,8 @@ static void __init_memblock memblock_merge_regions(struct memblock_type *type)
this->size += next->size;
memmove(next, next + 1, (type->cnt - (i + 1)) * sizeof(*next));
/* move forward from next + 1, index of which is i + 2 */
memmove(next, next + 1, (type->cnt - (i + 2)) * sizeof(*next));
Supports Markdown
0% or .
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment